(3y+4)(2y^2-1)=0

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Solution for (3y+4)(2y^2-1)=0 equation:


Simplifying
(3y + 4)(2y2 + -1) = 0

Reorder the terms:
(4 + 3y)(2y2 + -1) = 0

Reorder the terms:
(4 + 3y)(-1 + 2y2) = 0

Multiply (4 + 3y) * (-1 + 2y2)
(4(-1 + 2y2) + 3y * (-1 + 2y2)) = 0
((-1 * 4 + 2y2 * 4) + 3y * (-1 + 2y2)) = 0
((-4 + 8y2) + 3y * (-1 + 2y2)) = 0
(-4 + 8y2 + (-1 * 3y + 2y2 * 3y)) = 0
(-4 + 8y2 + (-3y + 6y3)) = 0

Reorder the terms:
(-4 + -3y + 8y2 + 6y3) = 0
(-4 + -3y + 8y2 + 6y3) = 0

Solving
-4 + -3y + 8y2 + 6y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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